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7y^2+25y-20=0
a = 7; b = 25; c = -20;
Δ = b2-4ac
Δ = 252-4·7·(-20)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1185}}{2*7}=\frac{-25-\sqrt{1185}}{14} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1185}}{2*7}=\frac{-25+\sqrt{1185}}{14} $
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